维护代码时发现发现前人艺高人胆大，GOTO满天飞，着实费了力气才勉强理清了逻辑
由于未曾在生产中使用过GOTO及break、continue来实现多层跳出，所以写个demo记录学习下
示例代码
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| func main() {
fmt.Println("start")
LOOP1:
for j := 0; j < 10; j++ {
fmt.Println("leve 1: in ", j)
LOOP2:
for i := 0; i < 10; i++ {
time.Sleep(time.Second)
fmt.Println("level 2: in ", i, j)
if i == 1 {
fmt.Println("continue LOOP2")
continue LOOP2
}
if i == 3 {
fmt.Println("continue LOOP1")
continue LOOP1
}
if j == 1 {
fmt.Println("break LOOP2")
break LOOP2
}
if j == 2 {
fmt.Println("goto GOTO1")
goto GOTO1
}
if j == 3 {
fmt.Println("goto GOTO2")
goto GOTO2
}
fmt.Println("level 2: over ", i, j)
}
GOTO1:
fmt.Println("leve 1: out ", j)
}
fmt.Println("before GOTO2")
GOTO2:
fmt.Println("over")
}
|
输出
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| start
leve 1: in 0
level 2: in 0 0
level 2: over 0 0
level 2: in 1 0
continue LOOP2
level 2: in 2 0
level 2: over 2 0
level 2: in 3 0
continue LOOP1
leve 1: in 1
level 2: in 0 1
break LOOP2
leve 1: out 1
leve 1: in 2
level 2: in 0 2
goto GOTO1
leve 1: out 2
leve 1: in 3
level 2: in 0 3
goto GOTO2
over
Process finished with exit code 0
|
捎带
break label
- label必须写在代码块的前面
- 直接跳出循环，即不再执行label所标记的循环
break LOOP2 之后 输出 leve 1: out 1，即是跳出了内部的for循环goto label
- 直接跳到label处执行，中间环境忽略
before GOTO2 并未打印，被跳过不执行continue label
- label必须写在代码块的前面
- 继续执行下一次的循环，忽略本次循环后续的所有逻辑
原文链接